Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation:...

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Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation: N2(g) + 3H2(g) +

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Answer 1

Answer #1

N2(g) + 3H2(g) ------> 2NH3(g)

Stoichiometrically, 1mole of N2 react with 3moles of H2

Number of moles = mass / molar mass

number of moles of N2 = 1200g/28.014g/mol = 42.836mol

number of moles of H2 = 590g/2.016g/mol = 292.66mol

292.66moles of H2 require 97.553moles of N2 but available moles of N2 is 42.836. So,

Limiting reagent is H2

Stoichiometrically, 3moles of H2 gives 2moles of NH3

moles of NH3 obtained by 42.836moles of H2 = (2/3)×42.836mol = 28.557mol

Mass of NH3 that can be maximum produced = 28.557mol × 17.031g/mol

= 486.34 g

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Answer 2

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