Ammonia can be synthesized from nitrogen and hydrogen according
to the following balanced chemical equation:
N2(g) + 3H2(g) →
2NH3(g)
At a particular instant, NH3 is being produced at a rate
of 0.50 M/min. What is the correct expression for the reaction
rate?
| 0.25 M/min |
| 0.50 M/min |
| 1.0 M/min |
| 1.5 M/min |
| 0.33 M/min |
Given rate of production of NH3 is 0.50M/min.
From the equation
N2 + 3H2 ---> 2NH3
Rate = - d[N2]/dt = -1/3 d[H2] /dt= 1/2 d[NH3] /dt
Now 1/2 d[NH3]/dt =0.50M/min
so d[NH3]/dt = 2*0.50M/min
=1.0 M/min (Ans)
Ammonia can be synthesized from nitrogen and hydrogen according to the following balanced chemical equation: N2(g)...
Ammonia (NH3) is produced by the reaction of nitrogen and hydrogen according to the chemical equation: N2+ 3H2 → 2NH3. What mass of nitrogen is necessary to react completely with 100.0 g of hydrogen?
Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation: N2(g) + 3H2(g) + 2NH3 (9) a What is the maximum mass of ammonia that can be produced from a mixture of 1.20 x 103 g N2 and 5.90 x 102 g H2? Mass = g
Nitrogen and hydrogen react to form ammonia according to the following balanced equation: N2(g)+3H2(g)=2NH3(g). Calculate the number of moles of hydrogen required to react with 0.0723 mole of nitrogen, and the number of moles of ammonia that will form.
26.) Ammonia is produced by the reaction of hydrogen and nitrogen as follows: N2(g)+3H2(g)→2NH3(g)ammonia Express the number of moles to two significant figures. (A.) How many moles of H2 are needed to react with 1.0 mol of N2? (B.) How many moles of N2 reacted if 0.50 mol of NH3 is produced? (C.) How many moles of NH3 are produced when 1.7 mol of H2 reacts?
Consider the following balanced reaction between hydrogen and nitrogen to form ammonia: 3H2(g) + N2(g)→2NH3(g) How many moles of NH3 can be produced from 18.0 mol of H2 and excess N2? Express the number of moles to three significant figures
Consider the following balanced reaction between hydrogen and nitrogen to form ammonia: 3H2(g) + N2(g)→2NH3(g) How many moles of NH3 can be produced from 18.0 mol of H2 and excess N2? Express the number of moles to three significant figures
Ammonia is produced by the reaction of nitrogen and hydrogen according to the equation N2(g) + 3H2(g) → 2NH3(g) Calculate the mass of ammonia produced when 32.0 g of nitrogen react with 13.5 g of hydrogen. ___________NH3 Which is the excess reactant and how much of it will be left over when the reaction is complete? hydrogen or nitrogen ________ g
In the Haber process, ammonia is synthesized from nitrogen and hydrogen: N2(g) + 3H2(g) → 2NH3(g) ΔG° at 298 K for this reaction is -33.3 kJ/mol. The value of ΔG at 298 K for a reaction mixture that consists of 1.9 atm N2, 1.6 atm H2, and 0.65 atm NH3 is ________. -3.86 × 103 -1.8 -7.25 × 103 -104.5 -40.5
Ammonia gas is synthesized by combining hydrogen and nitrogen: 3H2(g) + ϩN2 (g) -> 2NH3 (g) To produce 562g of NH3, what volume of air (the source of N2) is required if the air is introduced at 29 C and 99.3kPa? (Assume the air sample has 78.1 mol% N2)
Hydrogen gas, H2, reacts with nitrogen gas, N2, to form ammonia gas, NH3, according to the equation 3H2(g)+N2(g)→2NH3(g) NOTE: Throughout this tutorial use molar masses expressed to five significant figures. How many molecules (not moles) of NH3 are produced from 4.21×10−4 g of H2?