Question

Given that the solubility reaction for calcium phosphate is Ca3(PO4)2(s) = 3Ca2+ (aq) + 2PO43- (aq) why does the addition of acid increase the solubility of calcium phosphate? View Available Hint(s) O It decreases the phosphate ion concentration, forcing the equilibrium to the right It decreases the phosphate ion concentration, forcing the equilibrium to the left. O It increases the phosphate ion concentration, forcing the equilibrium to the right. It increases the phosphate ion concentration, forcing equilibrium to the left. O It decreases the calcium ion concentration, forcing the equilibrium to the right. It increases the calcium ion concentration, forcing the equilibrium to the right O It decreases the calcium ion concentration, forcing the equilibrium to the left. It increases the calcium ion concentration, forcing equilibrium to the left.

Answer 1

Given that the solubility reaction for calcium phosphate is Ca3(PO4)2(s) = 3Ca2+ (aq) + 2PO43- (aq) why does the addition of acid increase the solubility of calcium phosphate? View Available Hint(s) It decreases the phosphate ion concentration, forcing the equilibrium to the right | It decreases the phosphate ion concentration, forcing the equilibrium to the left. O It increases the phosphate ion concentration, forcing the equilibrium to the right. It increases the phosphate ion concentration, forcing equilibrium to the left. O It decreases the calcium ion concentration, forcing the equilibrium to the right. It increases the calcium ion concentration, forcing the equilibrium to the right O It decreases the calcium ion concentration, forcing the equilibrium to the left. It increases the calcium ion concentration, forcing equilibrium to the left.

Addition of an acid into the equilibrium,results in formation of $HPO_{4}^{2-}$ which decreases the phosphate ion concentration in the equilibriu. To maintain the system into equilibrium, more of the solid compound gets dissociated into ions resulting an increase in solubility of calcium phosphate.

Part C -

The net ionic equation for the dissolution of $FePO_{4}$ in $H_{3}O^{+}$ is-

FePo4 (5) + Algo a Fe 5€ +HPO.+ too 24 coal (1) ca aq) NE 3 coa)