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2. In the circuit below, use the node-voltage method to find v, and the power dissipated the 1092 resistor 5 VA 2012 - e 15V(
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Answer #1

o] given 202 A i + v. suor 14 150 Ⓡ at Methode Node Node voltage A apply V -15 V VA = 2 + I = 0 20 from son circuit I = 0.125Now apply KVL in dotted loop VA+5 VA + Vo =0 a Vo=-40 → Vo = -0.25V, put Vain Equation © 0.55[-0-25 v.] +0.125 Vo = 0.75 -0.0

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