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A 1000-VA, 230/115-V has the following equivalent circuit parameters Referred to high...
Problem 1 | (30 points) followery A test 10,000 VA 115/230v transformer has the data Short-cacuit...
Problem 1 | (30 points) followery A test 10,000 VA 115/230v transformer has the data Short-cacuit 1 Open Current test Vse av Isc=104 Pse = 40 W Voc= 1151 Ioc=0.54 Poc=10w a) Find the equivalent carunt referred to the high voltage side 6) find the equivalent circut referred to the low voltage side Assume Shag = 10KVA and Voace = 230v on high Voltage side Find the equise bhut cjuit in per-unit 1) Using per-unit circuits fröd the wolting regulation...
A 2.2KVA 600/120 V, transformer has the following data for its OC test and SC test:...
A 2.2KVA 600/120 V, transformer has the following data for its OC test and SC test: OC Test: Voc: 120V Ioc: 0.6A Poc: 16W SC Test Vsc = 12V Isc = 3.67A Psc= 30W (a) Find the equivalent circuit referred to its HV and LV side. (b) If it operating as a step-down transformer, and delivering its rated current at the rated voltage and 0.85 pf lagging, find what will be the input voltage. (c) Find the Voltage regulation of...
The following data was obtained when open circuit and short circuit tests were performed on a...
The following data was obtained when open circuit and short circuit tests were performed on a single phase, 50 KVA, 2,400:240 V, 60 Hz distribution transformer: With high voltage winding open circuited: Voc = 240 V, Ioc = 4.85 A, Poc = 173 W With low voltage winding short circuited: Vsc = 52 V, Isc = 20.8 A, Psc = 650 W a) Determine the equivalent circuit of the transformer referred to its high voltage side and to its low...
A 1000-VA 230/115-V transformer has been tested to determine its equivalent circuit. The results of the...
A 1000-VA 230/115-V transformer has been tested to determine its equivalent circuit. The results of the tests are shown below Open-circuit test Voc= 230 V loc= 0.45 A Poc 30 W Short-circuit test Vsc= 19.1 V lsc=8.7 A Psc= 42.3 W All data given were taken from the primary side of the transformer. Determine all the transformer parameters shown in Fig. 3. jXM Ns V. Ideal transformer Fig. 3
A 20 kVA, 60 Hz, 2400/240 V single-phase distribution transformer has been tested to determine its...
A 20 kVA, 60 Hz, 2400/240 V single-phase distribution transformer has been tested to determine its equivalent circuit. The results of the test are shown below: Open circuit Test (on low voltage side) Voc=240V, Ioc=1.028A, Poc=122W. Short circuit test (On high voltage side) Vsc=61.3V, Isc=8.33A, Psc=257W. The transformer is supplying power to a load that draws 15 kVA at 240 V. The load power factor is 0.90 lagging. Calculate the voltage regulation for this operation condition.
A 5 MVA 230/13.8 kV, single-phase transformer has a per-unit resistance of 1% and a per-unit...
A 5 MVA 230/13.8 kV, single-phase transformer has a per-unit resistance of 1% and a per-unit reactance of 5%. The open-circuit test performed on the low voltage side of the transfromer yielded the following data: VOC=13.8 kV, IOC=21.1 A, and POC=90.8 kW. (a) Find the equivalent circuit referred to the high voltage side of this transformer. (b) If the transformer is operating at full-load and at 0.8 pf lagging, find the voltage regulation of the transformer at this operating condition.
Problem 1 A 60Hz transformer is rated 30 (kVA), 4000(V)/120(V). The open circuit test, with the...
Problem 1 A 60Hz transformer is rated 30 (kVA), 4000(V)/120(V). The open circuit test, with the high voltage side open, gives Po= 100 (W), loc = 1.1455 (A). The short circuit test, measured with the low voltage side shorted, gives Pse = 180 (W), Vse = 129.79 (V). a) Determine the equivalent circuit for the transformer (both open and short circuit) b) Calculate the circuit components. (Req, Xeq, Rc, Xm)
Electric Machinery Problem 2: [50 points] A 15-KVA, 230/2300-V transformer is considered. The following test data...
Electric Machinery
Problem 2: [50 points] A 15-KVA, 230/2300-V transformer is considered. The following test data have been taken: | OC Test (on Primary) Voc = 230 V loc = 2.8 A Poc = 100 W SC Test (on Secondary) Vsc = 47 V Isc = 9.5 A Psc = 350 W (a) Find the equivalent circuit of this transformer referred to the high- voltage side. [10 points] (b) Find the equivalent circuit of this transformer referred to the low-...
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 po...
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 points) Draw the equivalent circuit. (1 point each) Find Ssc, QSC, Soc, Qoc, R1, R2, XI, X2, Rc, Xm, PFsc, PFoc, (esc θ。c) phase angel between V and I. What is the power rating of this transformer? Short circuit test (performed at High Voltage side) Vsc 16.20V rms, Isc 5.00 A...
I have these data from Open circuit and Short circuit tests: OCT: Voc= 105.9 v Ioc=...
I have these data from Open circuit and Short circuit tests:
OCT:
Voc= 105.9 v
Ioc= 0.08 A
Poc= 2 W
SCT:
Vsc= 12.9 V
Isc= 0.45 A
Psc= 3 W
pf= 0.669
How to correclty calculate the following
parameters:
The transformer rating
is
a. winding polarities b. core resistance and magnetization losses c. flux linkage losses d. winding resistances e. efficiency f. voltage regulation
Problem 1 | (30 points) followery A test 10,000 VA 115/230v transformer has the data Short-cacuit 1 Open Current test Vse av Isc=104 Pse = 40 W Voc= 1151 Ioc=0.54 Poc=10w a) Find the equivalent carunt referred to the high voltage side 6) find the equivalent circut referred to the low voltage side Assume Shag = 10KVA and Voace = 230v on high Voltage side Find the equise bhut cjuit in per-unit 1) Using per-unit circuits fröd the wolting regulation...
A 1000-VA 230/115-V transformer has been tested to determine its equivalent circuit. The results of the tests are shown below Open-circuit test Voc= 230 V loc= 0.45 A Poc 30 W Short-circuit test Vsc= 19.1 V lsc=8.7 A Psc= 42.3 W All data given were taken from the primary side of the transformer. Determine all the transformer parameters shown in Fig. 3. jXM Ns V. Ideal transformer Fig. 3
Problem 1 A 60Hz transformer is rated 30 (kVA), 4000(V)/120(V). The open circuit test, with the high voltage side open, gives Po= 100 (W), loc = 1.1455 (A). The short circuit test, measured with the low voltage side shorted, gives Pse = 180 (W), Vse = 129.79 (V). a) Determine the equivalent circuit for the transformer (both open and short circuit) b) Calculate the circuit components. (Req, Xeq, Rc, Xm)
Electric Machinery
Problem 2: [50 points] A 15-KVA, 230/2300-V transformer is considered. The following test data have been taken: | OC Test (on Primary) Voc = 230 V loc = 2.8 A Poc = 100 W SC Test (on Secondary) Vsc = 47 V Isc = 9.5 A Psc = 350 W (a) Find the equivalent circuit of this transformer referred to the high- voltage side. [10 points] (b) Find the equivalent circuit of this transformer referred to the low-...
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 points) Draw the equivalent circuit. (1 point each) Find Ssc, QSC, Soc, Qoc, R1, R2, XI, X2, Rc, Xm, PFsc, PFoc, (esc θ。c) phase angel between V and I. What is the power rating of this transformer? Short circuit test (performed at High Voltage side) Vsc 16.20V rms, Isc 5.00 A...
I have these data from Open circuit and Short circuit tests:
OCT:
Voc= 105.9 v
Ioc= 0.08 A
Poc= 2 W
SCT:
Vsc= 12.9 V
Isc= 0.45 A
Psc= 3 W
pf= 0.669
How to correclty calculate the following
parameters:
The transformer rating
is
a. winding polarities b. core resistance and magnetization losses c. flux linkage losses d. winding resistances e. efficiency f. voltage regulation
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