Question

WRITE A PROGRAM IN C++ THAT DECLARES AN INTEGER VECTOR V

1.)INITIALIZE THE VECTOR, V, WITH 10 INTEGERS WITH VALUES FROM 1 TO 10

2.)OUTPUT THE VECTOR IN DESCENDING ORDER, THEN ASCENDING ORDER

2.)ADD ALL THE EVEN NUMBERS
3.)ADD ALL THE ODD NUMBERS

4.)OUTPUT THE SUM OF EVEN INTEGERS

5.)OUTPUT THE SUM OF ODD INTEGERS

7.)OUTPUT THE PRODUCT OF EVEN INTEGERS

8.)OUTPUT THE PRODUCT OF ODD INTEGERS

SAMPLE:

Vector:

2 4 3 5 2 3 8 9 1 10
Ascending Order: 1 2 2 3 3 4 5 8 9 10

Descending order: 10 9 8 5 4 3 3 2 2 1

Even Sum: 2 + 4 + 2 + 8 + 10 = 26

Odd Sum: 3 + 5 + 3 + 9 + 1 = 21

Even PRODUCT: 2 * 4 *  2 * 8 * 10 = 1280

Odd PRODUCT: 3 * 5 * 3 * 9 * 1 = 405

Answer 1

#include <iostream>
#include <bits/stdc++.h>
using namespace std;

int main() {
vector<int> v{2 ,4 ,3 ,5 ,2 ,3 ,8 ,9 ,1 ,10};
// v.push_back(2);
// v.push_back(4);
// v.push_back(3);
// v.push_back(5);
// v.push_back(2);
// v.push_back(3);
// v.push_back(8);
// v.push_back(9);
// v.push_back(1);
// v.push_back(10);
sort(v.begin(), v.end());
cout << "Ascending \n";
for (auto x : v)
cout << x << " ";

cout<<endl;
  
sort(v.begin(), v.end(), greater<int>());
cout << "Descending \n";
for (auto x : v)
cout << x << " ";
  
cout<<endl;
int even=0;
for(int i=0;i<v.size();i++){
if(v[i]%2==0){
even+=v[i];
}
}
cout<<"even sum"<<even<<endl;
  
int odd=0;
for(int i=0;i<v.size();i++){
if(v[i]%2!=0){
odd+=v[i];
}
}
cout<<"odd sum"<<odd<<endl;

int evenprod=1;

int oddprod=1;
for(int i=0;i<v.size();i++){
if(v[i]%2!=0){
oddprod*=v[i];
}
if(v[i]%2==0){
evenprod=evenprod*v[i];
  
}
}
cout<<"even product "<<evenprod<<endl;

cout<<"odd product "<<oddprod <<endl;

   return 0;
}