Question

solve c programing language with Output screeshort?

Develop a program that accepts integers from command line and uses fork() to
have 4 child processes that will do sorting the integers into ascending order,
computing the sum of the integers, and counting the number
of even numbers and the number of odd numbers respectively.

Answer 1

Answer:

c code:

#include <stdio.h>
#include<unistd.h>
int main()
{
    int n;
    printf("Enter the n value ");  
    scanf("%d",&n);                                       //Reading number of integers
    printf("Enter the values into the array ");                 
    int a[n];
    for(int i=0;i<n;i++)
    {
        scanf("%d",a[i]);                                 //Reading integers into the array
    }
    n1=fork();
    n2=fork();
    if(n1==0 && n2>0)
    {
        int tmp=0;
        for(int i=0;i<n;i++)
        {
            for(int j=i+1;j<n;j++)
            {
                if(a[i]>a[j])
                {
                    tmp=a[i];
                    a[i]=a[j];                            //main process executing and sorting in ascending order
                    a[j]=tmp;
                }
            }
        }
        printf("sorted in Ascending order");
        for(int i=0;i<n;i++)
          printf("%d ",a[i]);
    }
    else if(n1>0 && n2==0)
    {
        int sum=0;
        for(int i=0;i<n;i++)
          sum+=a[i];                                    //child process 1 executing and computing sum of integers
        printf("sum is %d",sum);
    }
    else if(n1==0 && n2==0)
    {
        int eve=0;
        for(int i=0;i<n;i++)
        {
            if(a[i]%2==0)                              //child process 2 executing and counting even integers
              eve++;
        }
        printf("Number of even integers are %d",eve);
    }
    else if(n1>0 && n2>0)
    {
         int odd=0;
        for(int i=0;i<n;i++)
        {
            if(a[i]%2!=0)                              //child process 3 executing and counting odd integers
              odd++;
        }
        printf("Number of odd integers are %d",odd);
    }
   return 0;
}

Execution screenshots:

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