Question

Write a program in C that takes a file name as the only argument on the command line, and prints out the number of 0-bits and 1-bits in the file

int main ( int argc , char * argv [] ) {

// Check if the user gave an argument , otherwise print " ERROR : no argument "

// Check if the file can be read , otherwise print " ERROR : can ’t read "

// Otherwise , use a loop to read each character of the file // For each character count the number of 0: s and 1: s .

// Print out the total number of 0: s and 1: s in the file , as a decimal number

}

Answer 1

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
FILE *filePtr;
char ch;
int countZero = 0;
int countOne = 0;
  
if(argc < 2) // 1st argument is: argv[0] = ./a.out, argv[1] = fileName.txt
printf("ERROR : no argument");
else
{
// number of argument is correct; check if file can be read
filePtr = fopen(argv[1], "r");
if (filePtr == NULL)
{
printf("ERROR : file can't be read %s\n", argv[1]);
exit(0);
}
  
// file can be read
ch = fgetc(filePtr);
while(ch != EOF)
{
if(ch == '0')
countZero++;
else if(ch == '1')
countOne++;
  
ch = fgetc(filePtr);
}
fclose(filePtr);
  
// display the counts of zeros and ones in the file
printf("Number of 0's in the file: %d\n", countZero);
printf("Number of 1's in the file: %d\n", countOne);
}

return 0;
}

*************************************************************** SCREENSHOT ************************************************************

CONSOLE OUTPUT:

Number of O's in the file: 32 Number of l's in the file: 34 ... Program finished with exit code o Press ENTER to exit console.

INPUT FILE: (input.txt)

main.c input.txt 1 1 111100001101000001111111110001222888 2 779001222199905500111117889033221110 3 4452200800001110044041156911900330175