
(S3)(s4) The response of the system is given by Y(s) s(s+2)(2s 1) Find the initial value...
Given the system transfer f unction: G, (s) -2S+2) S+4 a) Plot the response y(t) for a step input of amplitude 4 for t=[0:0.01:21 b) Verify that the plot is correct using the initial and final value theorems. o) Repeat steps q.and b for G, (s)0S(S + 4). Remember, in input is a step of c) Repeat steps a and b for G2 (S) S+2 amplitude 4.
Automatic Course.. Please answer
S4 The differential equation that de s cribe Control System is given as y is the system out fut and u is the where inPut signal a) Find the system resPonse yct),if the input Signal is unit step at t 2 scend Uelue b) what is the outPut
Find the first six partial sums S1, S2. S3, S4, S5, S. of the sequence. 1 1 1 1 3° 32' 33 34 3 Give your answers as fractions. S, = S2 S3 = S4= Ss = So
Find the inverse Laplace transforms of
(a)
(b)
(c)
s 1 (2s +1) Y(s) = (822 5s + 8 (2s - 2) 21) Y(s) = Find the inverse Laplace transforms of (2s- 3)e-3,s 1) (2s (a) Y(s)2s+ ) (2s - 2) (c) Y(s) = (5-7)2
s 1 (2s +1)
Y(s) = (822 5s + 8 (2s - 2)
21) Y(s) =
Find the inverse Laplace transforms of (2s- 3)e-3,s 1) (2s (a) Y(s)2s+ ) (2s - 2) (c) Y(s) =...
Given s = j, find magnitude and phase of Y(s)=2+541 3. s4+s+1
(1 point) Calculate S3, S4, and Sg and then find the sum for the telescoping series 1 1 S (+12) n=4 where Sk is the partial sum using the first k values of n. S3 = S4= S5= S =
Question S) Compute the initial and final value of the system using the properties and verify the answer with the impulse response: Note for all these functions the ROC is Re(s) >O. S+3 s3+3s2 +2s 10 b) G(s)= 25
A linear system is governed by the given initial value problem. Find the transfer function H(s) for the system and the impulse response function h(t) and give a formula for the solution to the initial value problem. y" - 6y' +34y = g(t); y(O)= 0, y' (O) = 5 Find the transfer function. H(s) = Use the convolution theorem to obtain a formula for the solution to the given initial value problem, where g(t) is piecewise continuous on (0,00) and...
Consider the initial value problem Let L[y(t)] = Y(3), then Y(s) equals Select one: 2s +2 a. O b. 3s +1 s(232 + s +3) 2s2 + s +1 OC s(2s2 + 8 +3) O d. 2s +1-2/3 252 +8 e. 28 +1 -4/5 28² +8
You found the solution to the initial value problem to be -2s S 1 [e y(t) = L-1 94 +10 Evaluate y(1). O y(1) = 1 Oy(1) = -1 O y(1) = 0 y(1) = -2 Oy(1) = 2