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Determine the average rate of change of B fromt 0sto t 342 s Concentration of A (M) 0.780 0.450 0.120 Time (s) A2 B 342 M/s
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Answer #1

Answer:

Given reaction is

A -----> 2B

Rate=-∆[A]/∆t=(1/2)∆[B]/∆t

Now you have to find t=0 to t=342 s

Rate= -([A](342s) -[A](0s))/(342 s - 0s)

Rate=-(0.120-0.780)M/342 s

Rate=0.001929 M s^-1.

Now ∆[B]/∆t=2 x ∆[A]/∆t=2 x 0.001929 M s^-1.

∆[B]/∆t=0.003859 M s^-1 or 3.86 x10^-3 M/s.

Please let me know if you have any doubt. Thanks

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