Question

The rate of decomposition of acetaldehyde, CH2CHO(g), into CH4 (g) and CO(g) in the presence of I,(g) at 800 K follows the ra

0 0
Add a comment Improve this question Transcribed image text
Answer #1

10 Galyst - I o Stelt

Add a comment
Know the answer?
Add Answer to:
The rate of decomposition of acetaldehyde, CH2CHO(g), into CH4 (g) and CO(g) in the presence of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The mechanism of the pyrolysis of acetaldehyde corresponding to the chemical reaction CH3CHO(8) CH4(8) +CO(g) at...

    The mechanism of the pyrolysis of acetaldehyde corresponding to the chemical reaction CH3CHO(8) CH4(8) +CO(g) at 520 °C and 0.2 bar is kị kg CHCH0g) CH3 g) + CH0g) CH3(g) + CH3CHO(g) = CH4(g) + CH3COg) CH3CO(g) = CO(g) + CH3(g) CH3(g) + CH3(g) = C2H6() Is this reaction a chain reaction? If so, identify the initiation, propagation, inhibition, and termination step(s). Using the steady state approximation for intermediate species CH3(g) and CH3CO(g), derive the rate law 1/2 kz [CH2CHO]3/2

  • 6. [20pt] The Rice-Herzfeld mechanism for the thermal decomposition of acetaldehyde (CH:CНO) is k1 CH3CHO CH3...

    6. [20pt] The Rice-Herzfeld mechanism for the thermal decomposition of acetaldehyde (CH:CНO) is k1 CH3CHO CH3 CHO k2 CH3:: + CH3CНО $ СН4 + CH-CHO- k3 CH2CHO CO CH3 k4 СH3: + CH3. $ C2Н6 Using the steady-state approximation for the intermediates and determine the differential rate law for the formation of methane (CH4). State the expression for the effective rate constant, keff

  • A sample of hydroiodic acid has a concentration of 1.46 M and a density of 1.25...

    A sample of hydroiodic acid has a concentration of 1.46 M and a density of 1.25 g/mL. IF 50.0 ml s of this sample is removed and diluted with 155 ml.s of water (density = 1.00 g/mL), what is the molarity of the new sample? The decomposition of acetaldehyde (CH:CHO) is proposed to occur via a two-step mechanism. Step 1: CH3CHO + 12 + CH3 + HI + CO Step 2: CHI + HI – CH4 + 12 Which species...

  • 1. [8 Marks The experimentally obtained rate law for the iodine-catalyzed decomposition of acetaldehyde is: R...

    1. [8 Marks The experimentally obtained rate law for the iodine-catalyzed decomposition of acetaldehyde is: R =k[2] [CH CHO (a) Can the following mechanism be used to explain the kinetics of this reaction? Show all your work and justify whenever necessary. Intermediates: I HI, CHOCO, CHE ki 121 Catalyst : Is 1 + CHỊCHO + H + CHICO CH,CO CH3 + CO CH + HÍ - CHI + 1 ki 21 + 1 CHu + co CH₂ CHO 2. [7...

  • The following data were obtained for the decomposition of acetaldehyde CH3CHO → CH4 + CO Initial...

    The following data were obtained for the decomposition of acetaldehyde CH3CHO → CH4 + CO Initial Rate (mol L min-1) [CH3CHO] (mol L-4) 0.20 1.00 0.56 2.00 Which one of the following statements is correct? O A. The reaction is second order. O O B. The rate constant is 0.693 mol L-4 min-?. O C. The rate constant is 0.20 mol-1/2 L 1/2 min-?. O O O D. The reaction is first order. O E. The rate constant is 0.20...

  • Sav The thermal decomposition of acetaldehyde, CH3CHO -- CH4 + Co, is a second-order reaction with...

    Sav The thermal decomposition of acetaldehyde, CH3CHO -- CH4 + Co, is a second-order reaction with a rate constant of 6.67 x 10-2 M1s1 Starting with 1.00 M acetaldehyde, what is the half-life of this reaction? a. 7.0 5 b. 0.033s c. 0.067 s d. 1.0 x 10's e. 155 What is the boiling point of a solution containing 0.852 g naphthalene (C10H8, Molar Mass 128.2 g/mol) a nonvolatile, nonelectrolyte dissolved in 14.0 g benzene (Molar Mass = 78.1 g/mol)?...

  • I want the answer by using steady-state approximation < thank u in advance I reaction for...

    I want the answer by using steady-state approximation < thank u in advance I reaction for the thermal decomposition of acetaldehyde is: CH3CHO ·→ CH4 + CO A sequence of elementary steps proposed to explain the decomposition is as follows CH3CHO CH3' +CH3CHO CH3 +CH3 Derive an expression for the overall rate of decomposition of CH3CHO. Example 2. Ethyl nitrate pyrolysis has the following mechanism CH3'+ C2HsONO2 What is the rate expression consistent with this mechanism?

  • 3. Acetaldehyde decomposes to methane and carbon monoxide according to the following balanced equation: CH3CHO CH4...

    3. Acetaldehyde decomposes to methane and carbon monoxide according to the following balanced equation: CH3CHO CH4 + CO In a particular experiment, the following kinetic data for the decomposition of acetaldehyde were obtained: Time(s) 1000 2000 3000 4000 [CH,CнO] (м) What is the value of the rate constant at the temperature of this experiment? Give an answer with concentration units of molarity and time units of seconds. 0.3960 0.1423 0.0868 0.0624 0.0487 Submit Answer Tries 0/99

  • 1. For the reaction, CO, (g) 4 H2 (g) measured: CH4 (g) 2 HO (g), the following kinetic data are ...

    1. For the reaction, CO, (g) 4 H2 (g) measured: CH4 (g) 2 HO (g), the following kinetic data are HJ 0.00500 M 0.00500 M 0.00250M 0.0100 M CO.] 0.00250 M 0.00750 M 0.00750 M 0.00250 M Temperature 500 K 500 K 500 K 450 K Rate 5.2 x 10 M/s 1.6 x 103 M/s 2.1 x 104 M/s 2x 10 M/s Based on this data, a) determine the rate law for the reaction (4 pts), b) calculate the rate...

  • The gas phase decomposition of ethanol to acetaldehyde CH3CH2OH(g) → CH3CHO(g) + H2(g) occurs at 200...

    The gas phase decomposition of ethanol to acetaldehyde CH3CH2OH(g) → CH3CHO(g) + H2(g) occurs at 200 degrees C through a first order reaction with a rate constant of 0.028 min−1. If a container at 200oC is filled with 3.4 Atm of CH3CH2OH(g). What is the TOTAL pressure in the container after 30 minutes?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT