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Please solve the following Question using mainly the equations attached and the drawing amplitude must be a value not an equation, the value should be taken from the table?

Pre-work: Read Section 4.1, 4.1.1, 4.1.2 of Principles of Communications by Ziemer and Tranter. A Bessel function table is gi

Equations:

Depending on the value of the modulation index ß, we may distinguish two cases of frequency modulation: 1. Narrowband FM, for

For an arbitrary value of the modulation index B, it can be shown that the above equation (2) can be rewritten as s(t) = 4, Ž

44,(B) AGB AJ (8) AJB) Amplitude * 4 Jello 14:40 AJB) AJB) AJ_468) AJB) 1 AJB) 16-45m fe-2m fc+fm S+ + ***+ * t5c-4m 5.-

Appendix Table of Bessel Functions n = 0.05 8 = 0. 1 8 -0.2 -0.3 0 0.999 0.999 0.990 0.978 1 0.025 0.060 0.1000.148 0.001 0.0

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Answer #1

given mit)= Am cos Caafmt) and ß=0-3 we know that - ß <«L- Narrow band Fm ß>1-) wide baund im here ß=0-341 so it is narrow ba- IA 8=1 so n=1tß=1+1=2 & SFmc8) ACJOLI T ACJILI ACJ2 (1) ACJ-2013 I 2 T fe-dm fc-2&m fc ACJILD 7$ fethem fet2fm 6 h ß=3 , so- IA 8=1 so n=1tß=1+1=2 & SFmc8) ACJOLI T ACJILI ACJ2 (1) ACJ-2013 I 2 T fe-dm fc-2&m fc ACJILD 7$ fethem fet2fm 6 h ß=3 , so

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