Question

Provide an explanation (with drawings) why the reaction on the below yields the Hofmann product exclusively (no Zaitsev product at all) even though the base is not sterically hindered (bulky). Br NaOET in ELOH Predict the possible products of the following reactions and identify which product(s) will be the major product(s). You will need to evaluate to what extent substitution and elimination reactions occur. Pay close attention to stereochemistry when necessary. Br НО NatOEt (a) BuOK Na Ome (b) aa H.SO, heat Na* -OH (c)

Answer 1

solution : NoOEH 9η ειΗΟΗ En blontation of reaction goes according to Zaitsev i.e. base abstract proton a, then leaving group - Br is just Parallel to a proton If reaction goes according to Haffman le base abstract protan b then leaving group Br is anti to b protan which is more easier and more favourable Hoan a. That is reason, major product is Haffman product. e come No ome OH + Buok H2SO f) Healt