In series circuit emax =120 V
Resistance R =50 ohms
The capacitance C = 20 micro farad
The inductance L = 0.15 H
And the frequency of the generator f =60 HZ
Now the capacitive reactance XC = 1/2πfc
Xc = 1/(2π*60*20*10^-6)
Xc = 132.629 ohms
This is the capacitance reactance
b)
The inductive reactance is
XL = 2πfL
XL = 2*π*60*0.15
XL = 56.54 ohms
This is the indicative reactance
C) now the impedance of the circuit
Z = R + j( XL - Xc )
Z = R + j ( 56.54 - 132.629)
Z = (50 - j 76.089 ) ohms
This is the impedance of the circuit
The magnitude of the impedance is

Z = 91.046 ohms
d) rms voltage of the power supply
VRMS = 120 /√2 = 84.85 V
Now the Rms current in the circuit will be
I rms = Vrms / Z = 84.85 / 91.046 = 0.9319 A
IRMS = 0.9319 A
This is the Rms current of the circuit
Help please!! . cenerator GO a tor GO -1200V) is connected to Soare -1200 4. (16...
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