Question

6. The carapace widths of Limulus horseshoe crabs were measured. The mi = 28 males had a mean carapace width of x = 21.7 cm and a standard deviation of s1 = 5.5 cm. The n2 = 34 females had a mean carapace width of X = 24.1 cm with a standard deviation of s2 = 6.0 cm. Test the hypothesis of no difference in the mean carapace widths of males and females at the 5% level of significance. (3 points)

Answer 1

ag. I, Not no Here, the test show is - Ho: M M = 0 - T= (1, 2) - (M, M4) where Spe= (n-1) s + (m-1) 42 _ tntm-2). Here, X = 21.7 cm, S = 5.5cm, n, = 28. X= 24.1cm , 52= 60 cm, n2 = 34. _

T= (21.7 -24.1) 27,5.5°+ 33x31 33.4125 Spa (10-1) 5.5*+(34-) € (28+34-2). Sp: 5.78 = -2.4 5.78 10.06512 T= = 1.63 - 2.4 --163 5.78 x 0.2552 We will reject to in favour of ", if It> t ntm-2 where to, n.-mt denote, the upper 2 % point of a theme diste In this case, we need to find toots, so = 2:003 Since, It<2.003, we do not reject 1 and at 5% level a significance, we can say that there is no difference in me mean carapace widhs of males and females PLEASE LIKE THE ANSWER.