
X 107 kg) 27.25 A proton (q 1.60 x 1019 C, m 1.67 moves in a uniform magnetic field B (0.500 T)1. At t = 0 the proton has velocity components ux-1.50 × 105 m/s, vy=0, and vz = 2.00 × 105 m/s (see Example 27.4) (a) what are the magnitude and direction of the magnetic force acting on the proton? In addition to the magnetic field there is a uniform electric field in the +x-direction, E (+2.00 x 104...
A proton with charge 1.602 x 10^-19 C moves at a speed of 300 m/s in a magnetic field at an angle of 65 degrees. If the strength of the magnetic field is 19 T, what would be the magnitude of the force the charge experiences? 8.28 x 10^-16 N 13.78 x 10^-15 N 5.09 x 10^-14 N 7.75 x 10^-17 N An alpha particle travelling at 2155 m/s enters a magnetic field of strength 12.2 T. The particle is...
Consider the path of the proton (q = 1.602 × 10−19 C, m = 1.673 × 10−27 kg) in a uniform electric and magnetic field. Both fields are in the z direction, B⃗ = B0k? and E⃗ = E0k?, where B0 = 55 mT and E0 = 180 V / m. At time t = 0, the proton moves at v⃗ = v0?ı, v0 = 150 km / s. Based on this information, what kind of orbit does the proton...
8. A proton enters perpendicular to a magnetic field at 4.50 x 10 m/s that causes it to move in a circular path, due to a magnetic force of 1.85 x 10' N. When the proton is traveling in a circle it produces a current 1.05 x 10- A. What is the strength of the magnetic field? What is the radius of the circle? What is the torque on the proton? (16 pts)
A proton moves in a circle with a speed of 430 m/s through a uniform magnetic field of 2.0 T directed perpendicular to the circular path. 1) What is the orbital radius of the proton? (Express your answer using two significant figures.) (units in micro m)
A proton moves at 8.00×10^7 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 1 m. What is the field strength?
A proton moves at 7.20 ✕ 107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.810 m. What is the field strength (in T)?
A proton moves at 7.90 ✕ 107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.840 m. What is the field strength (in T)?
A cosmic-ray proton moves at 2.8 × 107 m/s perpendicular to Earth’s magnetic field at an altitude where the field strength is 1.75 × 10−5 T. What is the radius of the circular path the proton follows? Draw a diagram to explain your answer.
A proton moves in a circular orbit 150 mm in radius that is perpendicular to a uniform 0.25 T magnetic field. a. What is the speed of the proton? b. How long does it take for the proton to move once in a circle? c. Would the radius increase or decrease if the proton were heavier? d. Would the radius increase or decrease if the magnetic field were larger? e. Does the speed change if the proton were negatively charged?...