Question

1 loop, and 1 selection

Below are a list of sequences of numbers. Your job is to program each sequence with any loop of your preference (while, for, do/while). I want the code to output the sequence provided and the next number in the sequence (you can output more but there is 1 sequence that may only have 1 number after). . Each sequence should be in the same main in one .cpp file. . Please order and notate each sequence in your output – if you skip one for whatever reason, output the series number and leave the rest blank. The output should also be horizontal like that shown below (if you output it vertically it will be -10pts). Each sequence should be programed with only 1 loop and optionally 1 selection statement.

Series 1:

15, 14, 13, 12, 11, ...

Series 2:

1, 2, 5, 14, 41, ...

Series 3:

2, 3, 5, 8, 12, 17, ...

Series 4:

15, 13, 11, 9, 7, ...

Series 5:

71, 142, 283, 564, 1125, 2246, 4487, 8968, ...

Answer 1

Program code:

//header files
#include <iostream>
#include<cmath>
using namespace std;

//main method
int main(void)
{
   //variable used to print series
   int i,num,diff;
   num=15;
   //printing the details of series
   cout<<"Series 1:"<<endl;
   for(i=num;i>=0;i--){
       cout<<i<<", ";
   }
   //printing the details of series
   cout<<"\nSeries 2:"<<endl;
   num=1;
   for(i=0;i<=10;i++){
       cout<<num<<", ";
       diff=pow(3,i);
       num=num+diff;
   }
   //printing the details of series
   cout<<"\nSeries 3:"<<endl;
   diff=0;
   num=2;
   for(i=1;i<=10;i++){
       cout<<(num=num+diff)<<", ";
       diff++;
   }
   //printing the details of series
   cout<<"\nSeries 4:"<<endl;
   for(i=15;i>=0;i=i-2){
       cout<<i<<", ";
   }  
   //printing the details of series
   cout<<"\nSeries 5:"<<endl;
   diff=0;
   num=71;
   for(i=1;i<=10;i++){
       cout<<(num=(num*2)-diff)<<", ";
       diff++;
   }

   return 0;
}

Output: