volume of solution required to prepare = 153.9 ml , required w/v% = 5.40%
we know formula mass of solute in gram = (volume of solution in ml x w/v%)/100
substitute values to find gram of potassium fluoride solute required
mass of potassium fluoride solute required = (153.9 x 5.40)/100 = 8.3106 gram
ans 8.3106 gram of potassium fluoride is required to prepare 153.9 ml of 5.40 % (w/v) solution of potassium fluoride
calculate the amount of Potassium Fluoride (MW=58.1) required to prepare a 153.9 mL of a 5.40%...
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Calculate the osomolarity of 0.5 g/mL of magnesium sulfate
heltahydrate (MgSO4*7H2O) MW= 246.47 g/mol
Calculate the osmolarity of 1 Liter of solution that contains
40mEq of sodium, 20 mEq of potassium, 60 mEq of chlorine and 5% w/v
of dextrose (mol way: 180 non-electrolyte).
My teacher gave me the answer but I didn't understand how they
got it. thank you.
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