Question

Help needed for Wittig Reaction Synthesizing 9-(2-Phenylethenyl)anthracene:

ce 9-anthraldehyde Benzyltriphenylphosphonium chloride 9-(2-phenylethenyl)anthracene

Answer 1

" 50% m ""V (mass: volume) of NaoH means In 100 ml solution 50g NaoH present therefore in 1 ml solution 50/100 NaoH present therefore In 0.31 ml solution 50 times 0.31/100 NaoH present = 0.155 g NaoH Now, molar mass of NaoH = 40g/mol therefore Number of mol of NaoH is 0.155g NaoH = 0.155/40g/mol = 0.0039 mol Now since according to above reaction 1 mol NaoH produces 1 mol 9 - (2 - phenylethanyl) anthracnose therefore 0.0039 NaoH produces 0.0039 therefore Answer is 0.0039 mol \r\n Ans: (CH_3)_2 C = 0 & Ph_3 P = CH Ph If a reaction takes place on an unessyterical compound, different pathways are possible & among then one path way get predominary, known as region reflective reaction so region reflective is less relative therefore Answer: less reflective, region reflective "