M = 3.42
t = 1.72
sM = √(0.452/21) =
0.1
μ = M ± t(sM)
μ = 3.42 ± 1.72*0.1
μ = 3.42 ± 0.1694
90% CI [3.2506, 3.5894].
Une tho standard o mal dstritution or thtdstritution to construct a 9 con idence interval tor...
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WSUIT Help Use the standard normal distribution or the distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results In a random sample of 13 mortgage institutions, the mean interest rate was 3.56% and the standard deviation was 0.37%. Assume the...