Question

1. Enter two integer arrays: array1-129, 0, -56, 4, -7 and array2-19, 12, -36, -2, 12 3. Write the code to form and display another array array3 in which each element is the sum of numbers in the position in both arrays. Use pointers and functions: get array0. process arrays0 and show array0 (50 points)

i need help writing these programs in c++ format

Answer 1

1.

Code:

#include<iostream>
using namespace std;
int size;
void get_array(int *array)
{
   cout<<"Enter elements: ";
   for(int i=0;i<size;i++) cin>>*(array+i);
}
void process_arrays(int *array1, int *array2, int *array3)
{
   for(int i=0;i<size;i++)
   {
       *(array3+i) = *(array1+i) + *(array2+i);
   }
}
void show_array(int *array)
{
   for(int i=0;i<size;i++) cout<<*(array+i)<<" ";
}
int main()
{
   cout<<"Enter size: ";cin>>size;
   int *array1, *array2, *array3;
   array1 = new int[size];//allocate memory
   array2 = new int[size];
   array3 = new int[size];
   get_array(array1);//read arrays
   get_array(array2);
   process_arrays(array1, array2, array3);//generate array3
   show_array(array3);
}

Output:

Enter size: 5 Enter elements: 29 e-56 47 Enter elements: 9 12-36 -2 12 38 12-92 2 5 cess exited after 17.11 seconds with return value e Pro Press any key to continue . . .

2.

(k/10ⁿ)%10 gives nth digit in a number

Code:

#include<iostream>

using namespace std;

int main()
{
   int num;
   while(1)
   {
       cin>>num;
       if(num<0) break;
       cout<<"digits are: ";
       int k=num;
       cout<<(k/10000)%10<<" "<<(k/1000)%10<<" "<<(k/100)%10<<" "<<(k/10)%10<<" "<<k%10<<endl;
       int sum=0;
       sum=sum + (k/10000)%10 + (k/1000)%10 + (k/100)%10 + (k/10)%10 + k%10;
       cout<<"sum of digits: "<<sum<<endl;
   }
}

Output:

23546 igits are: 2 35 46 sum of digits: 20 98482 digits are: 98482 sum of digits: 31 98231 digits are: 90231 sum of digits: 15 Process exited after 22.29 seconds with return value 0 Press any key to continue . . .