Question

The figure below shows three charged spheres arranged along the y axis. (Assume q1-2.10 μC and q2 Express your answer in vector form.) 4.35 pC. 75.0 cm -4.80 uC 22.0 cm 12 (a) What is the electric field at x-0, y 2.50 m? N/C (b) What is the electric field at x 2.50 m, y 0? N/C

Answer 1

The eelectric filed due to the charge q, at the point (0,2.5 m) (9x10°)(2.1x10“), _ (9x10°)(2.1x 100) ; = (6.171x10 N/C) Î 4 7 (250 cm - 75 cm)?/- (1.75 m) The eelectric filed due to the charge q, at the point (0, 2.5 m) _kq, z _ (9x10°)(4.8x100),; _ (9x10°)(4.35x100), (2.5 m+22.0 cm )(O)== (2.72 m 2 )=(5.291x10° N/C) (j) The eelectric filed due to the charge q; at the point (0,2.5 m) _kq2 (_)_ (9x109)(4.35x10), _ (9x109)(4.35x100), 2(*)=(6.912x10° N/C) (-i) (2.5 m ) (2.5 m) The net electric field is, Ē = Ē, + Ē, +Ē; = (6.171x10' N/C) j+(5.291x109 N/C) (-1)+(6.912x10° N/C) (j) Ē = (4.55x10° ſ) N/C

(b) The directions of the electric fields at point (2.5 m, 0) is, E, sin , , E, cos , Ē, ..----, (2.5m01 N E cose E. 42 E, sin

The distance bewteen the charge q, and the point is 12.52 +0.752 = 2.61 m The distance bewteen the charge q, and the point is 12.52 +0.222 = 2.51 m From the figure, 75 cm ; 0 = 16.699 tano, = 250 cm tand, - 22 cm : A -5070 "2 250 cm From the figure, (9x10°)(2.1x10) 16.000) (9x10°)(4.35x10^)(5070)_(9x10°)(4.8*10*9) E = -(cos 16.699) + (2.5) = 1.932 x10 NC (2.61) (2.51)__(cos5.02º)-220)(4.8*109) (9x10°)(4.35x10°) in 5020 _(9x10°)(2.1x10). (sin 16.69) (2.51) (2.61) (9x10°)(4.35x10°)00875)_ (9x10^)(2.1x10) (0.287) (2.51) 9) (2.61) =-0.252x10 N/C - U. Ē = (1.932x10° i)-(0.252x10°;) NC