Concept - find the heat energy given by the
resistance . Use this heat energy to find the required temperature
after the given time using specific heat of water and aluminium as
shown below.
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Question 5 2 pts Aresistor has a voltage of 6 volts and a current of 3...
A 17.0 g piece of aluminum (which has a molar heat capacity of 24.03 J/°C·mol) is heated to 82.4°C and dropped into a calorimeter containing water (specific heat capacity of water is 4.18 J/g°C) initially at 22.3°C. The final temperature of the water is 25.3°C. Ignoring significant figures, calculate the mass of water in the calorimeter.
A 92.5 g piece of aluminum (which has a molar heat capacity of 24.03]/°C-mol) is heated to 624°C and dropped into a calorimeter containing water (specific heat capacity of water is 4.18 J/g°C) initially at 19.2°C. The final temperature of the water is 135.2°C. Ignoring significant figures, calculate the mass of water in the calorimeter.
b. A 92.5 g piece of aluminum (which has a molar heat capacity of 24.03 J/°C-mol) is heated to 621 and dropped into a calorimeter containing water (specific heat capacity of water is 1.10 MB initially at 19.2°C. The final temperature of the water is 135.2°C. Ignoring significant figures, calculate the mass of water in the calorimeter.
6. A piece of 155.0 g aluminium metal at 120°C was placed in a constant pressure calorimeter of negligible heat capacity containing 300.0 g of water at 20°C. Calculate the final temperature of the system (the aluminium metal and the water) in °C: given the specific heat of aluminium metal = 0.90 J/g °C, and that of water 4.184 J/g °C
5) A 125-g sample of an unknown mineral was heated to 102.5°C and placed into a calorimeter containing 85.0 g of water at 19.5°C. The heat capacity of the calorimeter was 13.9 J/°C. The final temperature in the calorimeter was 53.0"C. What is the specific heat of the mineral? Show work for partial credit. GADT 5) A 125-g sample of an unknown mineral was heated to 102.5°C and placed into a calorimeter containing 85.0 g of water at 19.5°C. The...
A 25.0-g block of ice at -15.00°C is dropped into a calorimeter (of negligible heat capacity) containing water at 15.00°C. When equilibrium is reached, the final temperature is 8.00°C. How much water did the calorimeter contain initially? The specific heat of ice is 2090 J/kg ∙ K, that of water is 4186 J/kg ∙ K, and the latent heat of fusion of water is 33.5 × 104 J/kg.
A student heats 64.73 g silver to 97.71 °C and carefully lowers it into a cup containing 78.69 g water at 23.26 °C. She measures the final temperature to be 26.46 °C. The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.76 J/°C. Assuming that there is no heating of the surroundings calculate the specific heat capacity of silver.
A 30.45−gstainless steel ball bearing at 103.2°C is placed in a constant-pressure calorimeter containing 121.9 g of water at 19.55°C. If the specific heat of the ball bearing is 0.474 J / (g·°C), calculate the final temperature of both the water and steel when they equilibrate. Assume the calorimeter to have negligible heat capacity.
Question 3 1 pts A coffee cup calorimeter is prepared, containing 100.000 g of water (specific heat capacity 4.184 J/g K) at initial temperature 80.000 C. A salt weighing 6.303 g is quickly added. The salt has a molar mass of 321.692 g/mol. The final temperature of the solution is 43.252 C. Assume no heat loss to the surroundings. Assume the specific heat capacity of the solution is equal to that of pure water, and that the mass of the...
Question 3 (1 point) Calculate the specific heat for the element Madeupium if the addition of 118.3J increases the temperature of a 13.8 g sample by 17.2 K A) 94.9 J/g°C B) 148 J/g°C OC) 0.498 J/g°C D) 2.01 J/g°C Question 4 (1 point) 0.839 g of an unknown organic liquid was burned in a bomb calorimeter, heating the 395 grams of water by 11.1°C. Assuming the calorimeter absorbs a negligible amount of heat, calculate the heat added to the...