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Using the differential equation approach, find io(80 ms) in the circuit in the figure below. 60 2H 12v (+) <120 242 t= 0 | t=

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OV So! O toorn SHA VC) GV At tror 33120 Elvin Zit) Apply Nodd at node ve » VR + 4 + v +6 =0 >> QV-24 + 3V+ V+6 =0 > 6V-18=0 Vf(t)= 3-10125787 Olt) at t= Box io3sec @csom) = - 101257 X 80** 6 (800) = 3-10125xe 0.64 (80m) = 3 - 10125 x 0.527= 3-0.592 1

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