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Exercise 3: (4 points) A product developer is interested in reducing the drying time of a primer paint. Two formulations of t
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Ex 3. ni = 10 X, 121 6= 12 N2 = 12 i- = (12 6, = 10 Ho: M. Vs Hh: Miy Mz Mg Пo 1· 8877 14.4 + 8.33 New, X = 0.05 So, Im, * ta

-(14-4x1-833) + (8.38x 1-76) 14.448.33 |· 8194 Since .t> t*., Ho is. nejècted. . M,- Mz = Cãi- Xq)±tx se CI a : %3D where SptAt &=0•05, tx= 1-725 (one- sided) (0.92,17.08) CI : 9±8.0842 > # The difference between means Cannot be Zero. Hence, popt fi

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