Question

a) The temperature of the steam at the turbine exit

Part 2 of 4 Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part Consider a steam power plant that operates on a reheat Rankine cycle and has a net power output of 80 MW. Steam enters the high-pressure turbine at 10 MPa and 500°C and the low-pressure turbine at 1 MPa and 500°C. Steam leaves the condenser as a saturated liquid at a pressure of 10 kPa. The isentropic efficiency of the turbine is 74 percent and that of the pump is 95 percent. 6.66 points eBook Determine the quality (or temperature, if superheated) of the steam at the turbine exit. Use steam tables. (You must provide an answer before moving on to the next part.) Hint References The temperature of the steam at the turbine exit is 'C.

b) Thermal efficiency of the cycle
c) the mass flow rate of the steam

Answer 1

at P, = 10kPa and aio ni = 19118 KIlig Na 0.00101 m3 kg wp-i = 4, (P2 - P.) 5000 OM Misen) Pump 10kPa 0.00101 (0000 - 10) - 0.95 10.62 K JIKA h2 = hit Woo - 19108 +10.62 - 202043 Kulky at P₂ = 10nRa and T- 500°c ng= 3375. 1 Kilig 53= 6.599 KJ lig.k. at Pus = 1MPa and Bus - 532 6.599 hus - 2783.5 kJ lies (Misen) t = hy-hy hz-hus 0.75 = 3375 1- hy 337501- 2783-5 hy = 2931-4 Kilk a 5 = 500°C and Ps= IMPa ng= 3479-1 Kilks S5= 7.764 kilig.k @ PGS = 10kpa and S6 S5 = 7.764 has = 246101 - hs-ho (Misen) t - hs- hos

0.75 = 347901 – no 347901 - 2461-1 no=2715-6 kilig at Po= 10 kPa q ho = 2715-6 Koles - To = 115c a) temperature of steam. To = 115°c ) b) Thermal efficiency of cycle Ith knet rin Hnet – HT-Wp Wy = (hz-hu) + Cho-ho) - (3375-1-2931-4) + (347961 - 271506) WTF 120702 kJ lig win = (ha-ha) & (ng-hu) - (337501- 202043) +(3499.1 - 0931.4) = 3720 37 Whet - 120722 - 10.62 = 1196.58 KJ/14 nu - 1196.58 0.32 16 = 132 -16% 7 3720 rate of the Steam (c) 80x1000 KITS 166.86 kJ/ man flow m' Winer. 1196.58 What