Homework Answers
Average rate:
dC/dt = C2-C1/(dt2-dt1) = (0.82-1)/(10-0) = -0.018 M/s
instantaneous rate at 60 s...
average between next 2 points:
dC/dt = C2-C1/(dt2-dt1) = (0.36-0.40)/(100) = -0.0004 M/s
dC/dt = C3-C2/(dt3-dt2) = (0.40-0.48)/(100) = -0.0008M/s
average = 0.0006 M/s
Q19
X must be a reactant, since it sconcentration is being lowered as time passes by
b
the rate is going slower, since the "slope" at initial times is steep
vs. the last time, which has almost a flat slope
c
absolute greater --> difference betwen 1-2 is greater than thatn of 2-3
(rate is slowing down)
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Part D
In a certain hypothetical experiment, the initial concentration
of the reactant R is 1.00 mol⋅L−1 , and its rate constant is 0.0150
mol⋅L−1⋅s−1. It follows a zero-order reaction mechanism for the
consumption of reactant R.
Plot the graph of concentration versus time. Consider the time
intervals as 0, 10, 20, 30, 40, and 50 s.
To sketch the graph first click on .
Then select the appropriate graph and plot the appropriate
points.
You don’t have to do every single problem. I would just like
help to get me started. So if there’s two or theee of almost the
same question then you can just do one of these. For an example for
the position graph; you only have to do problems: 1 , 2, 4, 6.
Thank you so much!
くBack Graphs-xt.pdfaビ山 Graph Practice Problems-x vs. t PHYS&114 Name: Complete all these problems on a separate sheet of paper. The graph represents...
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