Question

Two 1 1/2 V batteries are connected in parallel to a 3/omega resistor. How much current flows through each battery?

UPDATE : Figured it out ...."0.25 A"

Answer 1

Since both the batteries are connected in parallel combination:

So, Net potential across the resistor will be = 1.5 V

Thus : Total current flowing through the resistor is = 1.5 V / 3 Ohm = 0.50 A

And, Current flowing through each battery will be equal and of magnitude = 0.50 A / 2 = 0.25 A