Question

this is for a c++ program Ask the users for numbers until the total of the numbers is greater than 30. Also, count how many numbers are even and how many are odd. Total is 0 Please enter an integer: 20 Total is 20 Please enter an integer: 7 Total is 27 Please enter an integer: 2 Total is 29 Please enter an integer: 1 Total is 30 Please enter an integer: 1 You had 2 even numbers and 3 odd numbers.

Answer 1

Dear Student ,

As per the requirement submitted above , kindly find the below solution.

Here a new C++ program with name "main.cpp" is created, which contains following code.

main.cpp :

#include <iostream>
using namespace std;
int main()
{
int total=0;//variable to store sum
int evenCount=0;//variable to store even numbers count
int oddCount=0;//variable to store odd numbers count
int number;//variable to store number
//using while loop
while(total<30)
{
//asking user to enter number
cout<<"Please enter an integer:";
cin>>number;//reading number
total=total+number;//adding number in total
//checking for even and odd number
if(number%2==0)
{
evenCount++;//count number as even
}
else
{
oddCount++;//count number as odd
}
//display total
cout<<"Total is "<<total<<endl;
  
}
//print even and odd number count
cout<<"You had "<<evenCount<<" even numbers and "<<oddCount<<" odd numbers.";
return 0;
}

======================================================

Output : Compile and Run above program to get the screen as shown below

Screen 1 :main.cpp

input Please enter an integer:20 Total is 20 Please enter an integer:7 Total is 27 Please enter an integer:2 Total is 29 Please enter an integer:1 Total is 30 You had 2 even numbers and 2 odd numbers. ... Program finished with exit code o Press ENTER to exit console. I

NOTE : PLEASE FEEL FREE TO PROVIDE FEEDBACK ABOUT THE SOLUTION.