Question

C++ please no arrays!

Create a program that will allow the user to enter up to 50 whole values and determine the number of values entered, how many of the values were odd and how many of the values were even. Your code should contain 2 functions, a main function and a function to enter the numbers enter and count the values. Your main function should be a driver program that will call another function to count the total number of values entered, the number of even numbers entered, and the number of odd numbers entered, then output the values sent back to the function call. Use a function (other than main) that will prompt the user to enter up to 50 whole numbers values and count how many even and odd numbers were entered (0 should be considered an even number) utilizing a loop. The loop should continue as long as the user wants to enter another value and the number of values entered is less than 50. The function should send back to the function call how many values were entered and how many odd and even numbers were entered. Use a minimum number or arithmetic operators inside the loop, do not use multiplication or subtraction in the loop.

Please keep program as simple/basic as possible

Answer 1

Note: Could you plz go through this code and let me know if u need any changes in this.Thank You
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#include <fstream>
#include <iostream>
#include <iomanip>
#include <cstring>
#include <cstdlib>
using namespace std;

// Function Declarations
void getNos(int &cnt,int &cntEven,int &cntOdd);
int main() {
   //Declaring variables
   int cnt,cntEven,cntOdd;
  
   //calling the function
   getNos(cnt,cntEven,cntOdd);  
  
   cout<<"No of Values entered :"<<cnt<<endl;
   cout<<"No of Even Numbers :"<<cntEven<<endl;
   cout<<"No of Odd Numbers :"<<cntOdd<<endl;
   return 0;
}

/* This function will read and the numbers
* and count no of even nos and odd numbers entered
*/
void getNos(int &cnt,int &cntEven,int &cntOdd)
{
   int num;
   const int SENTINEL=-999;
   while(true)
   {
       cout<<"Enter a number (-999 to exit) :";
       cin>>num;
      
      
       if(cnt==50 || num==-999)
       {
           break;
       }
       else
       {
           cnt++;
          
           if(num==0 || num%2==0)
           {
               cntEven++;
           }
           else
           {
               cntOdd++;
           }
       }
   }
}

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Output:

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