Question

Problem #1 Write a program that prompts user to enter an integer up to 1000 and displays back a message about the number of digits in this number and if number is odd or even. For example, if user enters 93 message back should be "93 has 2 digits and is odd".

C++

Answer 1

#include<iostream>

using namespace std;

int main()

{

int num,i,count=0,n;

cout<<"\nEnter a number less than 1000 :";

cin>>num;

if(num<=1000)

{

n=num;

while(n!=0)

{

count++;

n=n/10;

}

if(num%2==0)

cout<<num<<" has "<<count<<" digits and is even";

else

cout<<num<<" has "<<count<<" digits and is odd";

}

else

cout<<"\nThe number entered is not in range ";

}

CppDroid project_feb25b.cpp Navigator Editor 1 #include<iostream> 2 using namespace std; 3 int main() 4{ 5 int num, i, count=0,n; 6 cout<<"\nEnter a number less than 1000 :"; 7 cin>>num; 8 if(num<=1000) 9{ 10 n=num; 11 while(n!=0) 12{ 13 count++; 14 n=n/10; 16 } 17 if(num%2==0) 18 cout<<num<<" has "<<count<<" digits and is even"; 19 else 20 cout<<num<<" has "<<count<<" digits and is odd"; 22 } 23 else 24 cout<<"\nThe number entered is not in range "; 25 26}

CppDroid terminal Stopped Enter a number less than 1000 :988 988 has 3 digits and is even

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