Question

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Consider the following unbalanced equation: O2(g) + C2H6(9) + CO2(g) + H20(1) If 24.7 moles of O2(g) reacts with an excess of C2H6(9), what is the theoretical yield of CO2(g) in moles? O 97.2 moles 14.1 moles 37.7 moles 88.6 moles O 26.8 moles

Answer 1

1. answer-14.1

11 2 C₂ H₂ + 7 - 4 og + 6H₂O 7 moles of Og gives 4 moles of cog. [ue 224g of Oz gives 176g of com] 24.7 moles of Oz = 4 x 24.7 moles of los = 14.11 moles of cog. Ans.

2.

1) Calculate mass of Ba in BaSO4:

(1.72 g) (137.33 g/mol / 233.39 g/mol) = 1.012 g

2) Calculate mass of anhydrous BaCl2 that contains 1.012 g of Ba:

137.33 g/mol Ba is present in 208.236 g/mol BaCl2

1.012 g is present in (208.236*1.012)/137.33 g BaCl2

x = 1.53 g

3) Calculate mass of water in original sample:

1.80 g − 1.53 g = 0.27 g

4) Calculate moles of anhydrous BaCl2 and water:

1.53 g / 208.236 g/mol = 0.0073 mol
0.27 g / 18.015 g/mol = 0.0150 mol

5) Express the above ratio in small whole numbers with BaCl2 set to a value of one:

BaCl2 ---> 0.0073 mol / 0.0073 mol = 1
H2O ---> 0.0150 mol/ 0.0073 mol = 2

BaCl2 · 2H2O

3. answer-80%

3 (aloz + 2HU - Calla t co₂t H₂O - Imole La coz gives Imole cog. 100g Calog gives ung cog. 1.0og caloz gives oung co2. - 0 Acc. to question 1.asy liniston gives 0.44g co. - so From ho - we can say that 1.35g limestone has log cao Ixloo - 180% ] Ans