Question

pls provide an answer and an explanation for the following questions. a good answer will get a good review. thank you

3. Use Trouton's rule to predict the enthalpy of vaporization of benzene at its normal boiling point of 80.1° C. 4. Calculate AS (for the system) when the state of 3.00 mol of gas molecules, for which Co.m = R, is changed from 25°C and 1.00 atm to 125°C and 5.00 atm. Let's do this by breaking it into two steps: (a) First, consider heating the initial system at constant pressure to the final temperature. What is AS associated with this change? (b) Next, consider an isothermal change in pressure. What is AS associated with this change? Hint: Since p < (1/V), you may re-write AS = nR In(V/V) as AS = n Rin(pi/p). (e) Find the total AS of the system by summing your above two answers.

Answer 1

3. To solve this question, it's important that one is aware of the premise of Trouton's rule.

Trouton's rule says that a liquid that doesn't involve hydrogen bonding and has a boiling point of greater than 150 K would have a molar entropy of vaporization of 10.5 times the value of the gas constant.

The best examples of liquids that follow Trouton's rule are benzene and toluene.

Mathematically,

Нар Дs = =

$\small \Delta 10.5 \times 8.314 JK^{-1}mol^{-1} =\frac{\Delta H_{vap}}{353.25 K}$

$\small \Delta H_{vap} = 30837.665 J mol^{-1} = 3.1 \times 10^{4} \, kJ mol^{-1}$

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