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Using the table of reduction potentials (Eo) for the half-reactions shown, match the given redox reactions with their Eo and

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Answer #1

NAD+ + H+ + 2e’ <====> NADH -0.32

1/2 O2 + 2H+ + 2e’ <====> H2O 0.816

Standard reduction potential = 0.816 V – (-0.032 V) = 1.14 V (exergonic reaction)

C6H12O6 (glucose) + 6 O2 -> 6 CO2 + 6 H2O

Standard reduction potential = -1.24 (exergonic reaction)

6CO2+12H2O--->C6H12O6+6O2+6H2O

Standard reduction potential = +1.24 (endergonic reaction)

FADH2FAD

Eo' = +0.15 V (endergonic reaction)

CoQH2 + 2 cytochrome c1 (Fe3+) + 2 H+ → CoQ + 2 cytochrome c1 (Fe2+) + 4 H+

Eo' = +1.00 V (endergonic reaction)

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