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KCl and KBr are both ionic solids. A mixture of KCl and KBr has a mass...

KCl and KBr are both ionic solids. A mixture of KCl and KBr has a mass of 3.595 g. When this mixture is heated in the presence of excess Cl2, all of the KBr is converted to KCl. If the total mass of KCl present after this reaction is 3.129 g, what percentage (by mass) of the original mixture was KBr? (HINT: Be sure that you understand why the mass of the sample has decreased. It may help if you write an equation for the reaction that converted the KBr to KCl.)

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Answer :-

This question is solved by using the simple concept of stoichiometry and a chemical equation is written then mass is calculated.

The answer is given in the image,

Answer: mass of Br+ku=$3.595g. 2kBr +cle → ekel + Br 39.1+79.90 39.1+35.45 = 119 g/mol = 74.55g/mol. het mass of kBr=xg. 2811

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