Question

7. Consider the reaction: 4A(g) + 2B(g) + C(g) + 3D(g) The reaction is prepared by making a vessel under the following conditions, [A] = 10.0 M, [B] = 8.00 M, [C] = 12.0M and [D] - 15.0M When equilibrium is achieved, the D1 = 8.4M. What is the value Key for the teachin (8)

Answer 1

Given reaction :- 4A49) + 2B699 = Cog) + 30g). from the balanced equation, 4 moles of A combined with 2 moles of B to form I mole of C and 3 mole of D. Initial concentration of A given = 10.0M. gmitial concentration of B given = 8.0om. gnitial concentration of a given = 12.0m gratial concentration of D given = 15.0m. Let x be the molao concentration of e pro duced at any time (tj. No. of moles of D produced will be .. za and 40 molecules of A and 200 moles of B must reacted then according to balcmce chemical equation. given Equation 4 Alg) + 2 B 9 Cig) + 3D g) 10.00 8.00m 12.00m 15.om at t=t (10.0-430)n. (8.00-2069m (12.00+200m (15.0+3069 m at too

At equilibrium :- concentration of [D] given = 8.4 m. Thus, at my time t, equilibrium is achieved. The concentration of CO] is a (15.0 + 300M= 8.4m. 15.0 + 330 = 8.4 . - 35c= 15.0 -8.4 30= 6.6 e a -ve value, 2 = -2.27 Ć That means deacreasein concentrations). So putting value of ac in concentrations of all other terms. Concentration of [A] = (10.0-4x3C)m - 10.0-4X (-2.2) = 10-0 + 8.8= 18.8 m. - concentration of Bit (8.00–22) M2 (8.00–2XC-2-22]M 3 (8.00+ 4.4) - 12.4m. concentration of C s. (12.00m +) (12-00 - 2.20ms 918 m.

for the given imaginary reaction :- Keq = [C]' [D] 3 [n] 4 [B]2 Putting value of concentrations of A, B, C $ $ after equilibrium is achieved, Koo keq = value of is 19.87 (8.4)3 = 0.005685 (18.8.14 (12:4)2 5.685x10-31 Keg when equilibrium is reached 5.685 x103 (approx.) (Please don't dislike