Question

Consider the following equilibrium.

A+2B⇌C+3D

If the change in concentration for C is 0.760 M, what will be the corresponding change in concentration (in units of molarity) for D?

• Round the answer to three significant figures.

Answer 1

Calculation:
Given the equilibrium reaction:

$$\text{A}+2\text{B}\rightleftharpoons \text{C}+3\text{D}$$

The stoichiometry shows that for every 1 mole of C produced, 3 moles of D are produced.

• Change in concentration for C ($\mathrm{\Delta }[\text{C}]$) = +0.760 M (since it is formed).

• 
  

• Change in concentration for D ($\mathrm{\Delta }[\text{D}]$) = $3\times \mathrm{\Delta }[\text{C}]=3\times 0.760\text{M}=2.28\text{M}$.

• 
  

Thus, the change in concentration for D is 2.28 M.

Answer:
The corresponding change in concentration for D is 2.28 M.