Question

A large skinny guy with mass 2M and a smaller guy with mass M are holding onto a massless pole while standing on frictionless _i ce, as shown_below. If the little guy_pulls himself 2M -3 m 0 m 3 m (2) -2 m (5) 1 m (8) None of the above (3) -1 m (4) 0 m (6) 2 m (7) 3 m

Answer 1

F = ma

For constant force,

Acceleration is inversely proportional to mass,

So acceleration of mass M is twice as that of 2M

Using 2md equation of motion

d = 0.5 at^2

For same value of time, distance is directly proportional to Acceleration produced

d_M = 2 d_{2M ... (i)}

Also, d_M + d_2M = 6

From (i)

3 d_2M = 6

d_2M = 2 m

Ordinate of this point becomes = (-3+2) = - 1 m

Option (3) is correct.

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