1nm = 10-9 m

Calculate how much 1 cm corresponds to for 20,000,000 magnification = 2 x 10(^7) magnification. Give...
The length is 12.5 cm and the magnification is 70,000 X. calculate the length of this cell in µm = micro-meters.
6.29 X 10 -34 93×10 2. A 505-nm photon is absorbed by an electron in an atom. By how much does the energy of the atom increase? ( 6.626 X 10 J-SX 3X1 the 505X10-9 nm 3. Solve Equation 2 for V. Express your result in the form y = mx where V corresponds to y and f corresponds to x a. Sketch (i.e., don't use data) a graph of V as a function of f. Use the back of...
39 points I Previous Answers SerCP11 23.5.P046. An object is placed 17:4 cm from a first converging lens of focal length 11.9 cm. A second converging lens with focal length $.00 em is placed 10.0 cm to the right of the first converging ens (a) Find the position q1 of the image formed by the first converging lens. (Enter your answer to at least two decimal places.) X cm (b) How far from the second lens is the im 27.64...
The next few questions give you the chance to use the Lens Equation that relates the object distance, Xo, image distance, Xi, and focal length of a lens, F, by: This equation comes from considering the ratio of side lengths of various triangles that are formed in ray diagrams of the type that you have been doing for the last week. There are a few rules you need to follow to play the game and to understand the results. Here...
Choose the green light first. λ = 5.461 x 10-7 meters
for green
Choose lens to “Grating distance” as 7 and
“Grading lines per nm” as 400 nm
Check the button “Grading in place”
Record I1 and I1’ to the table and
calculate an angle as average if you know both I1 and
I1’
(hint from your trig how to get your angle: tan-1
(Opposite / Adjacent) = θ(angle)
Find distance between I’1 and I1 and
divide in half to...
In the figure below, 91 = 1.70 x 10 -7 C and 92 = 3.70 x 10 -7 C. 91 92 - X (cm) 1 2 TT 3 4 5 6 7 8 1) What is the x component of the electric field e at the point (x, y) = (6.00 m, 3.00 m)? (Express your answer to three significant figures.) NOTE -- the figure is correctly labeled in centimeters and the question is asking for the E-field at (6,3)...
PLEASE ANSWER ALL OF THE QUESTIONS
Question 1 5 pts An object is placed 7 cm to the left of a converging lens with a focal length of 12 cm. What is the magnification of the final image with respect to the object? If the image is real, the magnification is negative. Please include the minus sign in the answer. Please round your answer to one decimal place. Question 7 5 pts A double slit is illuminated with monochromatic light...
5. A 2.0 cm high object is placed 10 cm in front of a lens. An upright image is formed by the lens and is located 20 cm from the lens. (a) (2 pts.) Is the image real or virtual? Explain. (b) (2 pts.) Calculate the focal length of the lens. (c) (2 pts.) Is the lens a converging or diverging lens, explain. (d) (2 pts.) Calculate the magnification of the image. (e) (2 pts.) Calculate the height of the...
calculate the magnification of fields 1 and 3, and the
field diameter of 2 . (hint. Use your ruler.) Note the the numbers
for the field diameters below are too large to represent the
typical compound microscope lens system, but the relationships
depicted are accurate
5 mm mm 0.5 mm 1.- 3.04 2.0 100 x X X
Convert the following measurement. 2 x 1 -7 kg.m 2.4 x 10 2 g cm