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Practical Differentiator Vout Figure 6 Practical Differentiator circuit To mitigate the problem of noise amplification at hig

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www. c Ro Intro vinthumny IP R2 Voul practical director * Derive a relation between Vin and Vout in Laplace Domain * De knowVin- o - o = -Vout 2 ZI or che z2 - Vout - Vin T(S) = -2 21 Z 2 Inverting Amplifier gain (shortent) - Vout Zz = Nin Ritha Vouif you have any doubt please comment below or if you don't understand anything about problem, thank you

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