Question

Calculate the map distances and determine the SCO and DCO classes: a+c: 91 a++: 504 abc:...

Calculate the map distances and determine the SCO and DCO classes:

a+c: 91

a++: 504

abc: 346

ab+: 342

+++: 343

++c: 344

+bc: 476

+b+: 79

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Answer #1

As there is a higher probability of having no crossover (NCO) ,the two genotype with the highest number of offspring are (NCO)

There are 2 sets of single crossover (SCO) and 2 with lowest offspring are double crossover (DCO).

arc :91 oco att : 504 Nco abc : 346 Sto (2) abr : 342 scocil +++ : 343 SCO(2) ++ C : 344 Scot) tbc : 476 Nco +b+ : 79 Dco Ifso the total map distance between 'a' and 'b' is 67.91 map units.

As 'c' is in between 'a'and'b' distance between 'a' and 'c' is 34.01 map units and between 'b' and 'c' is 33.9 map units

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