Question

A uniform rod with a mass of m = 1.73 kg and a length of l = 2.44 m is attached to a horizontal surface with a hinge. The rod can rotate around the hinge without friction. (See figure.) Initially the rod is held at rest at an angle of 0 = 70.3° with respect to the horizontal surface. Then the rod is released. What is the angular speed of the rod, when it lands on the horizontal surface? 7.56rad/s Submit Answer Incorrect. Tries 2/12 Previous Tries What is the angular acceleration of the rod, just before it touches the horizontal surface? 2.033 rad/s^2 Submit Answer Incorrect. Tries 3/12 Previous Tries

Answer 1

Centre of man ih= l sind Irina Reference final lire (U=o) Rotations for of Energy notion y conservation of Mechanical Energy Jor K.E. I + P. E. I = ki Eft P.E.F. 0 + mgh = I wp² to where h= l sind I-me2 Emo A Moment of - Inertia of Red about end) 39 sind = w p2 - wp= ( 39 sino og sma) = (hey wp where g=9.8mig? = 2.4um 0 - 70.3° 349.8 sin/70.3°) 2.44 2:05* 0.94 = 11:327 =) Wp = 3.36556 Redlove "Wp = 3.37 Rad see

of Angulor acceleration - rod just before Torque on rod touch su = 12 Tury Ing (g) ) = long - (Forcell perpendieber distance of action line of Erre force) 2= 32 39 20 = 3x9.8 2 x 9.44 12 = 6:02 Rad/see 2