A movie stunt driver on a motorcycle speeds horizontally off a 44.0 m high cliff. Determine the time it takes the motorcycle to leave the cliff top to land on the ground. Ignore air resistance. (g = 9.80 m/s2) Please explain.
as the speed of motorcycle is in horizontal direction, there is no vertical component of speed .
hence, only acceleration due to gravity is present in vertical direction.
applying 2nd equaion of motion,
s = u*t + 1/2*a*t2
where, u = 0 (in vertical direction)
s= 44 m
a = g= 9.8m/s2
so,
44 = 0+ 1/2*9.8*t2
t2 = 44*2/9.8 =8.979
t= 2.996 seconds
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