Question

Light with a wavelength of 432 nm is incident on a single slit with a width of 6.0 μm. If the intensity of the central bright fringe is 685 W/m2, find the intensity at these angular positions from the fringe. (a) 20.0 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. W/m2 (b) 40.0。 W/m2 (c) 60.0 W/m2

Answer 1

a) The angular location of the bright frn at 20.0 is, α--sin 20.00 10-*m 1msin 200 180 -9 432nm1 m nm sin (0.523rad) 432nm1 m nm - 21.79rad The intensity at this location is, Sin α sin 21.79rad) 21.79rad 685 Wm 5.75x102 W/m2

b. The angular location of the bright fringe at40.0 is. α--sin 40.00 10-5 1 um 180 432nm 10- 10-5 432nm 10- m(0698rad) nm = 28-042rad The intensity at this location is, Sin α nat (685 W/m2 sin 28.042rad 28.042rad -4.62 x102 W/m2

The angular location of the bright fringe at 60.0 is, α sin 60.00 10-6 180 432nm 10msin 60.00 Trad nm 10-5 432nm 10-mSIn(1.047 |- nm = 37.78rad The intensity at this location is, sin α (685 Wm2 sin 37.78rad) 37.78rad 3.13x10 Wm2