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According to a health organization in a certain​ country, 21.8​% of the population smoked in 2008....

According to a health organization in a certain​ country, 21.8​% of the population smoked in 2008. In​ 2014, a random sample of 650 citizens of this country was​ selected, 129 of whom smoked. Complete parts a through c below. a. Construct a 90​% confidence interval to estimate the actual proportion of people who smoked in this country in 2014. A 90​% confidence interval to estimate the actual proportion has a lower limit of nothing and an upper limit of nothing. b. What is the margin of error for this​ sample? The margin of error is nothing.

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Answer #1

Given Data P P. 21.8%. O 218 n650 129 a) 90%o Confidene Intual 129 O 1985 650 P Za/2 n .G45 O 1985(-0 A86) CJ 1986 t o 1590T1

p = 0.218 is between the values 0.173 and 0.224

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