Question

Here is data with y as the response variable. 55.1 79.1 76.4 43 79.3 65.2 69.7 42.7 77.5 61.9 15.9 146.6 66.6 87 90 75.6 65.2

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Answer #1

Scatterplot 160 140 120 100 80 60 40 20 20 40 60 0 80 100 X

Outlier = (15.9,146.6)

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without outlier

X Y (x-x̅)² (y-ȳ)² (x-x̅)(y-ȳ)
79.1 55.1 29.430625 123.766 -60.353125
76.4 43 7.425625 539.401 -63.288125
79.3 65.2 31.640625 1.051 -5.765625
69.7 42.7 15.800625 553.426 93.511875
77.5 61.9 14.630625 18.706 -16.543125
66.6 87 50.055625 431.601 -146.983125
75.6 90 3.705625 565.251 45.766875
65.2 84.9 71.825625 348.7556 -158.270625
ΣX ΣY Σ(x-x̅)² Σ(y-ȳ)² Σ(x-x̅)(y-ȳ)
total sum 589.4 529.8 224.515 2581.96 -311.925
mean 73.68 66.23 SSxx SSyy SSxy

sample size ,   n =   8          
here, x̅ = Σx / n=   73.68   ,     ȳ = Σy/n =   66.23  
                  
SSxx =    Σ(x-x̅)² =    224.5150          
SSxy=   Σ(x-x̅)(y-ȳ) =   -311.9          
                  
estimated slope , ß1 = SSxy/SSxx =   -311.9   /   224.515   =   -1.3893
                  
intercept,   ß0 = y̅-ß1* x̄ =   168.5837          
                  
so, regression line is   Ŷ =   168.584   +   -1.389   *x

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with outlier

X Y (x-x̅)² (y-ȳ)² (x-x̅)(y-ȳ)
79.1 55.1 140.290864 402.225 -237.546914
76.4 43 83.620864 1033.980 -294.044691
79.3 65.2 145.068642 99.113 -119.909136
69.7 42.7 5.975309 1053.363 -79.335802
77.5 61.9 104.948642 175.710 -135.795802
15.9 146.6 2637.393086 5104.309 -3669.069136
66.6 87 0.429753 140.291 -7.764691
75.6 90 69.629753 220.3575 123.868642
65.2 84.9 4.225 94.954 -20.030
ΣX ΣY Σ(x-x̅)² Σ(y-ȳ)² Σ(x-x̅)(y-ȳ)
total sum 605.3 676.4 3191.582222 8324.30 -4439.628
mean 67.26 75.16 SSxx SSyy SSxy

sample size ,   n =   9          
here, x̅ = Σx / n=   67.26   ,     ȳ = Σy/n =   75.16  
                  
SSxx =    Σ(x-x̅)² =    3191.5822          
SSxy=   Σ(x-x̅)(y-ȳ) =   -4439.6          
                  
estimated slope , ß1 = SSxy/SSxx =   -4439.6   /   3191.582   =   -1.3910
                  
intercept,   ß0 = y̅-ß1* x̄ =   168.7109          
                  
so, regression line is   Ŷ =   168.711 +   -1.391 *x
correlation coefficient ,    r = Sxy/√(Sx.Sy) =   -0.8613  
=======================

yes, the outlier appears to be an influential point

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