
Outlier = (15.9,146.6)
--------------------------------------------
without outlier
| X | Y | (x-x̅)² | (y-ȳ)² | (x-x̅)(y-ȳ) |
| 79.1 | 55.1 | 29.430625 | 123.766 | -60.353125 |
| 76.4 | 43 | 7.425625 | 539.401 | -63.288125 |
| 79.3 | 65.2 | 31.640625 | 1.051 | -5.765625 |
| 69.7 | 42.7 | 15.800625 | 553.426 | 93.511875 |
| 77.5 | 61.9 | 14.630625 | 18.706 | -16.543125 |
| 66.6 | 87 | 50.055625 | 431.601 | -146.983125 |
| 75.6 | 90 | 3.705625 | 565.251 | 45.766875 |
| 65.2 | 84.9 | 71.825625 | 348.7556 | -158.270625 |
| ΣX | ΣY | Σ(x-x̅)² | Σ(y-ȳ)² | Σ(x-x̅)(y-ȳ) | |
| total sum | 589.4 | 529.8 | 224.515 | 2581.96 | -311.925 |
| mean | 73.68 | 66.23 | SSxx | SSyy | SSxy |
sample size , n = 8
here, x̅ = Σx / n= 73.68 ,
ȳ = Σy/n = 66.23
SSxx = Σ(x-x̅)² = 224.5150
SSxy= Σ(x-x̅)(y-ȳ) = -311.9
estimated slope , ß1 = SSxy/SSxx = -311.9
/ 224.515 = -1.3893
intercept, ß0 = y̅-ß1* x̄ =
168.5837
so, regression line is Ŷ =
168.584 + -1.389 *x
-------------------------
with outlier
| X | Y | (x-x̅)² | (y-ȳ)² | (x-x̅)(y-ȳ) |
| 79.1 | 55.1 | 140.290864 | 402.225 | -237.546914 |
| 76.4 | 43 | 83.620864 | 1033.980 | -294.044691 |
| 79.3 | 65.2 | 145.068642 | 99.113 | -119.909136 |
| 69.7 | 42.7 | 5.975309 | 1053.363 | -79.335802 |
| 77.5 | 61.9 | 104.948642 | 175.710 | -135.795802 |
| 15.9 | 146.6 | 2637.393086 | 5104.309 | -3669.069136 |
| 66.6 | 87 | 0.429753 | 140.291 | -7.764691 |
| 75.6 | 90 | 69.629753 | 220.3575 | 123.868642 |
| 65.2 | 84.9 | 4.225 | 94.954 | -20.030 |
| ΣX | ΣY | Σ(x-x̅)² | Σ(y-ȳ)² | Σ(x-x̅)(y-ȳ) | |
| total sum | 605.3 | 676.4 | 3191.582222 | 8324.30 | -4439.628 |
| mean | 67.26 | 75.16 | SSxx | SSyy | SSxy |
sample size , n = 9
here, x̅ = Σx / n= 67.26 ,
ȳ = Σy/n = 75.16
SSxx = Σ(x-x̅)² = 3191.5822
SSxy= Σ(x-x̅)(y-ȳ) = -4439.6
estimated slope , ß1 = SSxy/SSxx = -4439.6
/ 3191.582 = -1.3910
intercept, ß0 = y̅-ß1* x̄ =
168.7109
so, regression line is Ŷ = 168.711
+ -1.391 *x
correlation coefficient , r = Sxy/√(Sx.Sy)
= -0.8613
=======================
yes, the outlier appears to be an influential point
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