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[3 1 0 -1] [3 1 0 -1] Same A = 3 1 -7 1 , and its row echelon form is U = 0 0 -7 2 . 16 2 0 -2] LO 0 0 0 ] 1. If C(A) is to b3. Find a basis for C(U) and a basis for C(A).

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olution an 14 A=131 0-17 te echleontoom is 3 lit 4. te U3 10-17 O 0- 72 LO 0 0 0 since columns of A are vectors in R. If ((A)As all conditions of subspace are satisfied CLA) is subspace of Rs. Q3 a) In matrix o, column 2 a) In matut is scalar multiplamal “) Tone ((A) = Clu) As elementau elementary now operation does not cho column space of matux. sis for c(0) = { 13.2013 a

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