How much does a 0.36 m long copper rod with a 7.7 mm diameter stretch when one end is fixed and the other is pulled with a 1.5 kN force
The Young Modulus for copper wire is
gama = 120*10^(9) Pa = (F/A)/ (delta L / L)
delta L = FL/(A gama) = 1.5*10^3 * 0.36 / (pi * 0.00385^2 * 120*10^9)
= 0.097*10^(-3) m
= 97 * 10^(-6) m = 97 um
How much does a 0.36 m long copper rod with a 7.7 mm diameter stretch when...
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2-m long rod. After applying the load, the diameter of the rod
decreases to 0.01998 m and the length increases to 2.01 m. The
engineering stress on that rod is most nearly:
PLEASE SHOW ALL WORK.
A tensile force of 120 leN is applied on a 0.02-m diameter and 2-mm long rod. After applying the load, the diameter of the rod decreases to 0.01998 m and the...