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In the figure (Figure 1) , C1 = C5 = 8.3 ?F and C2= C3= C4 = 4.2 ?F . The applied potential is Vab = 250 V .

A)Find Q1 Q2 Q3 Q4 Q5

B) Find V1 V2 V3 V4 V5

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Answer #1

C3 and C4 are in series and their series combination is given as

C34 = C3 C4 /(C3 + C4) = (4.2 x 4.2)/(4.2 + 4.2) = 2.1 uF

C34 and C2 are in parallel and their parallel combination is given as

C234 = C2 + C34 = 4.2 + 2.1 = 6.3 uF

C1 , C234 and C5 are in series and their series combination is given as

1/C12345 = 1/C1 + 1/C234 + 1/C5

1/C12345 = 1/8.3 + 1/6.3 + 1/8.3

C12345 = 2.5 uF

Qtotal = C12345 Vab = 2.5 x 250 = 625 uC

Q1= Q5 = Qtotal = 625 uC              since C1 and C5 are in series with Vab

V1 = V5 = Q1/C1 = 625 / 8.3 = 75.3 volts

V2 = Vab - V1 - V5 = 250 - 75.3 - 75.3 = 99.4 volts

Q2 = C2 V2 = 4.2 x 99.4 = 417.5 uC

Q3 = Q4 = Qtotal - Q2 = 625 - 417.5 = 207.5 uC

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