Question

Part (b)

Using m is 4.00 kg and r is 60.0 cm, calculate the gravitational potential energy in case 1 above.
Note that a number such as 1.23 x 10^-9 can be entered as 1.23e-9
_______ J

Answer 1

The concept is quite same as the electrostatic potential energy , there is no much difference in the calculating the gravitational energy and the electrostatic potential energy , so in our question just think we are assembling different masses so we have to do work in order to placed them at a certain position against the respective force due to other masses and that work is stored as a potential energy , So each mass will store some energy with other mass and the overall gravitational energy will be the sum of the potential energy of the individual masses .

Case 1 Am 2 m m= 4kg 1 4= 6oem conceptured (M)------M2) - - - - formula for Gravitation af potential or a particle having mass 'Ma placed at a distance er from a pantiele having Mass 'My taking from Infinity This means particle is taking from infinity to's'. U Gravitational potential energy

Solution: In our question there is an assembly on three Particles having mass 4m, 2m, m. so the gravitational potential stened in the Bystem or three mass is equal to Ug = - G (4m) (2m) - G12m) (m) - G14h) (m) = = G [ 8m² + 2m² + ame] - - G x ( 14 m2) a - 16.674X16 ") x(14) x( 4) (66x102)

Please upvote my answer , if you like ,by clicking on the like button